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　　AI進(jìn)??(jin)行??(xing)預(yù)??(yu)測(cè)??(ce)的??(de)邏??(luo)輯??(ji)基??(ji)礎(chǔ)?(chu)是??(shi)統(tǒng)??(tong)計(jì)??(ji)學(xué)??(xue)、機(jī)??(ji)器??(qi)學(xué)??(xue)習(xí)??(xi)和??(he)數(shù)??(shu)據(jù)??(ju)挖??(wa)掘??(jue)??，通??(tong)過(guò)??(guo)分??(fen)析??(xi)歷??(li)史??(shi)數(shù)??(shu)據(jù)??(ju)中??(zhong)的??(de)模??(mo)式??(shi)和??(he)規(guī)??(gui)律?(lv)??，推??(tui)斷??(duan)未??(wei)來(lái)??(lai)事??(shi)件??(jian)或??(huo)結(jié)??(jie)果??(guo)的??(de)可?(ke)能??(neng)性??(xing)??。??但??(dan)是??(shi)??，彩??(cai)票??(piao)每??(mei)次??(ci)開(kāi)??(kai)獎(jiǎng)??(jiang)具??(ju)有??(you)隨??(sui)機(jī)??(ji)性??(xing)和??(he)獨(dú)?(du)立??(li)性??(xing)??，往?(wang)期??(qi)開(kāi)??(kai)獎(jiǎng)??(jiang)數(shù)??(shu)據(jù)??(ju)與??(yu)未??(wei)來(lái)??(lai)開(kāi)??(kai)獎(jiǎng)??(jiang)結(jié)??(jie)果??(guo)之??(zhi)間??(jian)沒(méi)??(mei)有??(you)關(guān)??(guan)系??(xi)??，即??(ji)使??(shi)AI能??(neng)對(duì)??(dui)歷?(li)史?(shi)開(kāi)??(kai)獎(jiǎng)??(jiang)號(hào)??(hao)碼??(ma)進(jìn)??(jin)行??(xing)所??(suo)謂??(wei)的??(de)“復(fù)??(fu)雜??(za)”分??(fen)析??(xi)??，也??(ye)無(wú)??(wu)法??(fa)預(yù)??(yu)測(cè)??(ce)下??(xia)一??(yi)次??(ci)開(kāi)??(kai)獎(jiǎng)??(jiang)號(hào)??(hao)碼??(ma)??，因??(yin)為??(wei)彩??(cai)票??(piao)的??(de)每??(mei)次??(ci)開(kāi)??(kai)獎(jiǎng)??(jiang)都??(dou)是??(shi)獨(dú)??(du)立??(li)事?(shi)件??(jian)??，不??(bu)受??(shou)之??(zhi)前??(qian)結(jié)??(jie)果??(guo)的??(de)影??(ying)響??(xiang)??。那?(na)些??(xie)聲??(sheng)稱(chēng)??(cheng)用??(yong)AI能??(neng)預(yù)??(yu)測(cè)??(ce)中??(zhong)獎(jiǎng)??(jiang)號(hào)??(hao)碼??(ma)的??(de)不??(bu)法??(fa)分??(fen)子??(zi)??，只??(zhi)不??(bu)過(guò)??(guo)是??(shi)利??(li)用??(yong)了??(le)人??(ren)們??(men)渴??(ke)望??(wang)中??(zhong)獎(jiǎng)??(jiang)的??(de)心??(xin)理??(li)??，編??(bian)造?(zao)了??(le)一??(yi)個(gè)??(ge)看??(kan)似??(si)“科??(ke)學(xué)??(xue)”的??(de)騙??(pian)局??(ju)??。　　彩??(cai)票??(piao)是??(shi)一??(yi)種??(zhong)概??(gai)率??(lv)游??(you)戲??(xi)??，以?(yi)雙??(shuang)色??(se)球??(qiu)為??(wei)例??(li)??，按?(an)照祝(zhao)游??(you)戲??(xi)規(guī)??(gui)則??(ze)??，從??(cong)1-33個(gè)??(ge)紅??(hong)色??(se)球??(qiu)號(hào)??(hao)碼??(ma)中??(zhong)選??(xuan)擇?(ze)6個(gè)??(ge)、從??(cong)1-16個(gè)??(ge)藍(lán)??(lan)色??(se)球??(qiu)號(hào)??(hao)碼??(ma)中??(zhong)選??(xuan)擇??(ze)1個(gè)??(ge)組??(zu)成??(cheng)1注??(zhu)號(hào)?(hao)碼??(ma)?。??而??(er)這??(zhe)樣??(yang)的??(de)組??(zu)合??(he)數(shù)??(shu)有??(you)1772萬(wàn)??(wan)多??(duo)種?(zhong)??，每??(mei)一??(yi)種??(zhong)組??(zu)合??(he)有??(you)著??(zhe)相??(xiang)同??(tong)的?(de)中??(zhong)獎(jiǎng)??(jiang)概??(gai)率??(lv)?。并??(bing)且??(qie)??，每??(mei)次??(ci)開(kāi)??(kai)獎(jiǎng)??(jiang)都??(dou)是?(shi)一??(yi)次??(ci)獨(dú)??(du)立??(li)的??(de)隨??(sui)機(jī)??(ji)事??(shi)件?(jian)??，毫??(hao)無(wú)??(wu)規(guī)??(gui)律??(lv)可??(ke)言??(yan)?。。