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學習快評丨qibao666888　　蛋??(dan)白??(bai)質??(zhi)是??(shi)由??(you)氨??(an)基??(ji)酸??(suan)序??(xu)列??(lie)構??(gou)成??(cheng)的??(de)??，氨??(an)基??(ji)酸??(suan)序??(xu)列??(lie)的??(de)長??(chang)度?(du)從??(cong)數(shù)??(shu)百??(bai)個??(ge)到??(dao)上??(shang)千??(qian)個??(ge)不??(bu)等??(deng)??。??AI時??(shi)代??(dai)??，數(shù)??(shu)據?(ju)是??(shi)推?(tui)動??(dong)技??(ji)術??(shu)進??(jin)步??(bu)的??(de)核??(he)心??(xin)資??(zi)源??(yuan)??，龐??(pang)大??(da)的??(de)蛋?(dan)白??(bai)質??(zhi)序?(xu)列??(lie)數(shù)??(shu)據??(ju)集??(ji)能??(neng)幫??(bang)助??(zhu)模??(mo)型??(xing)更?(geng)好??(hao)地??(di)理??(li)解??(jie)蛋??(dan)白??(bai)質??(zhi)的??(de)序??(xu)列??(lie)、結?(jie)構??(gou)和??(he)功??(gong)能??(neng)關??(guan)系??(xi)??。洪??(hong)亮?(liang)團??(tuan)隊??(dui)建??(jian)立??(li)的?(de)蛋??(dan)白??(bai)質??(zhi)序??(xu)列??(lie)數(shù)??(shu)據??(ju)集??(ji)Venus-Pod(Venus-Protein Outsize Dataset)含??(han)有??(you)近??(jin)90億??(yi)條??(tiao)蛋??(dan)白??(bai)質??(zhi)序??(xu)列??(lie)??，包??(bao)含??(han)數(shù)??(shu)億??(yi)個?(ge)功??(gong)能??(neng)標?(biao)簽??(qian)??，是??(shi)全??(quan)球??(qiu)數(shù)??(shu)據??(ju)規(guī)??(gui)模??(mo)最??(zui)大??(da)、功??(gong)能??(neng)批??(pi)注??(zhu)標?(biao)簽??(qian)最?(zui)多??(duo)的??(de)數(shù)??(shu)據??(ju)集??(ji)??，也??(ye)是??(shi)另??(ling)一??(yi)行??(xing)業(yè)??(ye)知??(zhi)名??(ming)模?(mo)型??(xing)——美??(mei)國??(guo)ESM-C模??(mo)型??(xing)訓??(xun)練??(lian)用??(yong)的??(de)21億??(yi)蛋??(dan)白??(bai)質??(zhi)序??(xu)列??(lie)的??(de)4倍??(bei)體?(ti)量??(liang)???！　〉??(dan)白??(bai)質??(zhi)是??(shi)由??(you)20種??(zhong)氨??(an)基??(ji)酸??(suan)組??(zu)成??(cheng)的??(de)一??(yi)條??(tiao)高??(gao)分??(fen)子??(zi)鏈??(lian)?，這??(zhe)個??(ge)高??(gao)分??(fen)子??(zi)鏈祝(lian)會??(hui)扭?(niu)曲??(qu)并??(bing)折??(zhe)疊??(die)成??(cheng)獨?(du)特??(te)的??(de)三?(san)維??(wei)結??(jie)構??(gou)?，正??(zheng)是??(shi)這??(zhe)種??(zhong)獨??(du)特??(te)結?(jie)構??(gou)賦??(fu)予??(yu)了??(le)特??(te)定??(ding)蛋??(dan)白??(bai)質??(zhi)的??(de)生??(sheng)物??(wu)功??(gong)能?(neng)??。??要??(yao)設?(she)計??(ji)出?(chu)一??(yi)款?(kuan)成??(cheng)功??(gong)的??(de)蛋??(dan)白??(bai)質??(zhi)產?(chan)品??(pin)?，不?(bu)能??(neng)只?(zhi)關?(guan)注??(zhu)它??(ta)的??(de)三??(san)維??(wei)結??(jie)構??(gou)?，而??(er)是??(shi)要??(yao)能?(neng)成??(cheng)功??(gong)預??(yu)測??(ce)和?(he)設??(she)計??(ji)它??(ta)的??(de)功??(gong)能??(neng)??。洪??(hong)亮?(liang)團??(tuan)隊??(dui)直?(zhi)接??(jie)瞄??(miao)準??(zhun)“功??(gong)能?(neng)預??(yu)測??(ce)”這??(zhe)一?(yi)終??(zhong)極??(ji)目??(mu)標??(biao)?，將??(jiang)復??(fu)雜??(za)的??(de)蛋??(dan)白??(bai)質??(zhi)設??(she)計??(ji)變??(bian)成??(cheng)以??(yi)需??(xu)求??(qiu)為??(wei)導??(dao)向??(xiang)?，配??(pei)合??(he)少??(shao)量??(liang)實??(shi)驗??(yan)輸??(shu)出??(chu)結??(jie)果??(guo)的??(de)簡??(jian)單?(dan)過??(guo)程??(cheng)??。。